diketahui fungsi (3x + 2) = x akar x + 1, jika f'(x) turunan pertama fungsi f (x), nilai 12f'(11) ....

Halo Farasyatundaniss, aku bantu jawab ya. Jawaban: 11 Ingat! f(x) = u(x) . v(x) f'(x) = u'(x) . v(x) + u(x) . v'(x) Pembahasan: 3x + 2 = x 3x = x - 2 x = 1/3 (x - 2) f(3x + 2) = x√( x + 1) f(x) = 1/3 (x -2) √(1/3 (x -2) + 1) = 1/3 (x -2) √(1/3 x - 2/3 + 1) = 1/3 (x -2) √(1/3 x + 1/3) = 1/3 (x -2) √(1/9 (3x + 3)) = 1/3 (x - 2) 1/3 √(3x + 3) = 1/9 (x - 2) √(3x + 3) f'(x) = 1/9 √(3x + 3) + 1/9 . (x - 2) . 3/(2√(3x + 3)) f '(11) = 1/9 √(3(11) + 3) + 1/9 . (11 - 2) . 3/(2√(3(11) + 3)) f '(11) = 1/9 √36 + 1/9 . 9 . 3/(2√36) f '(11) = 6/9 + 3/12 f '(11) = 2/3 + 3/12 f '(11) = 8/12 + 3/12 f '(11) = 11/12 12 f'(11) = 12 . 11/12 12 f'(11) = 11 Dengan demikian diperoleh nilai dari 12 f'(11) = 11 Semoga membantu ya 😊