Pertanyaan

Nilai dari ∫ − 1 2 ​ ( 3 x 2 − 3 x + 1 ) d x a d a l ah ...

Nilai dari

 

  1. 3

  2. 5

  3. 7

  4. 9

  5. 17

N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

integral from negative 1 to 2 of open parentheses 3 x squared minus 2 x plus 1 close parentheses d x equals open square brackets 1 third.3 x cubed minus 1 half.2 x squared plus 1. x close square brackets subscript negative 1 end subscript superscript 2  equals open square brackets x cubed minus x squared plus x close square brackets subscript negative 1 end subscript superscript 2  equals open square brackets open parentheses 2 close parentheses cubed minus open parentheses 2 close parentheses squared plus 2 close square brackets minus open square brackets open parentheses negative 1 close parentheses cubed minus open parentheses negative 1 close parentheses squared plus left parenthesis negative 1 right parenthesis close square brackets  equals space 6 plus 3  equals 9

Iklan

Pertanyaan serupa

∫ 0 2 ​ x 2 d x =

Jawaban terverifikasi

Iklan

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia